TINTVERSITI SAINS
MALAYSIA
Peperiksaan Kursus Semasa Cuti Panjang Sidang Akademik 2002/2003
April2003
ZCT 3O4El3 - Keelektrikan dan Kemagnetan II
Masa :
3jam
Sila pastikan bahawa kertas peperiksaan
ini
mengandungiDUABELAS
muka surat yang bercetak sebelum anda memulakan peperiksaanini.
Jawab kesemua
LIMA soalan.
Pelajar dibenarkan menjawab semua soalan dalam batrasa InggerisATAU
bahasa MalaysiaATAU
kombinasi kedua-duanva.1. (a) Suatu
cakerabulat berjejari .R
mempunyai ketumpatan cas permukaan yang seragilmo.
Carikan medan elektrik pada satutitik
pada paksi cakerayang berjarak
z
dartsatahnya. (g/20)
(b)
Suatusilinder bulat
yang tegakberjejari R
danpanjang Z
diletakkan di sepanjangpaksi z.
Silinder tersebut mempunyai ketumpatan isipadu tak seragam yang diberikan dengan persamaanp(t)= p" +Pz
merujgk kepadatitik
asalan pada pusatsilinder.
Carikan daya keatas satutitik
casq
yang diletakkan pada pusat silindertersebut.
(*gunakan jawapan yang diperoteh daribahagian
(a)) eZ/20)
2.
Suatucas q ditaburkan
secara seragam pada keseluruhan suatuisipadu
sferaan bukan pengkonduksi yang mempunyaijejari n.
(a) Tunjukkan
bahawa keupayaan padatitik yang berjarak r
dari pusat, di manar
<R,
diberikan dengan persamarm.v -qQR' --:.') (rs/zo)
8neoR3
(b)
Apakah keupayaan padatitik r
>R?
(5120)85,
...2/-
lzcr
304E1-2-
3.
Dua petala konduktor sfera sepusatberjejari r, dan r,
ditetapkan pada keupayaanQr and Qz tiap-tiap satunya.
Kawasan antarapetala sfera
tersebutdi
penuhi dengan suatu bahan dielektrik.(a)
Dengan pengiraan terus, tuqiukkan tenaga yang tersimpan dalamdielektrik
adalah bersamaan denganc(q' : qt )'
.2
(b)
TentukanC,
kapasitans sistem tersebut diatas.(st20) (tst20)
(s/20) (s/20) (s/20) (s/20)
4'
Suatukabel
seqaksi yang panjangterdiri
daripada duakonduktor
sepusat denganjejarinya
sepertiditunjukkan
dalam rajatrdibawah. Kabel kondukttr-konduktor tersebut membawa arus i yang magnitudnya adalatr sama tetapi
arahnya bertentangan. Tentukan medan magnet Bdi r jika
(a) | 1a,
(b) a<r<b,
(c)
b<r <c
dan(d) r>c (diluarkabel)
...3/-
[zcT 3048]
-3-
5. Tunjukkan
keupayaanvektor
kemagnetanuntuk dua dawai panjang, lurus
dan selari yang membawa arusI
yang sama tetapi bertentangan arah diberikan oleh- u^I -/ \
2=X*17)r,
dimana r, dan r,
adalahjarak-jarak dari titik
medanke
dawai-dawai berkenaan dann
ialah vektorunit
selari dengan dawai-dawai tersebut.(20t20)
91
...4/-
lzcT
304E1TERIEMAHAN -4-
TINWERSITI
SAINSMALAYSIA Third
Semester Examination 2002/2003 Academic S essionApril2003
ZCT
304E,13- Electricity and Magnetism II
Time :
3 hoursPlease check that the examination paper consists
of TWELVE
printed pages before you commence this examination.Answer
ail FIVE questions.
Students areallowed to
answerall
questionsin
English OR bahasa Malaysia OR combinationsof
both.1.
(a) A
circular diskof radius R
has auniform
surface chargedensity o .
Findthe electrical
field
at apoint
on the axisof
the disk at a distancez
from theplane of the
disk. gl20)
(b) A right
circular cylinderof radius R
andheight Z
is orientedalong
the z -axis. It has a nonuniform volume density of charge giro"n
byp(r)=p.+Fz with
referenceto an origin at the
centerof the
cylinder.Find the force on a point charge g placed at the
centerof the
cylinder.(*hint
use the answer obtained fiom part (a))(r2t20)
A
charge4
is distributeduniformly
throughout a non-conducting spherical volume of radius .R.(a)
Show that the potential a distancer from
the center, wherer
<R
is givenby
v =qbn' - *)
SneoR' What is the potential at a
point r
>R?
(rs/20)
(b)
(s/20)
...51-
3.
- vcT
304E1-f-
Two
concentric, spherical, conducting shellsof radii r, and rz
are maintained atpotentials g, md
cp,respectively.
The region betweenthe
shellsis filled with
a dielectric medium.(a)
Show by direct calculation that the energy storedin
the dielectric is equal to^/ \?
L(9r -92,1-
2
O)
DetermineC,
the capacitance of the system.4.
A long coaxial
cable consistsof two
concentricshown below. There are equal and
opposite Determine the magneticfield B at r if
(a) r 1d,
(b)
a<r <b,
(c)
b<r <c
and(d) r >c
(outsidethe cable)(s/20) (rs/20)
conductors
with the
dimensionscurrents i in the
conductors.(s/20)
(st20) (s/20) (s/20)
93
...6/-[zcT
304E]5. Show that the magnetic vector potential for two long, staight, parallel
wires carrying the same current, ^Iin
opposite directions is given by- tt^I - (^\
A=rL^li )r,
where
r,
and\
are the distancesfrom
thefield point
to thewires,
andfi
is aunit
vector parallel to the wires.(20t20)
-6-
94
...7/-
-7
-tzcr
304E1LAMPIRAN
Mathematical Guidance
Possibly Useful Integrals:
tr Q-rp)dp l,z-r z+r- ],er+7 1;iP = 7r1z - rl" 14'
'f o, r., ,,
!,(r'
+ z2- 2zrp)t/;
=;(lz
+rl-lz -
r)) ldxlx
taw=7aw
lxe^dx="^lZ-41
" La a-J
Useful Constants
p
= -J_=
g.99*ro, N '?'
e
= r.6oxro-rec
4neo Ct
ao = 8.85x
tot'ft lro = 4x *tou T'!
A
95
...8/-
[zcT
304E]-8-
LAMPIRAN
Vector Calculus
Cartesian Coordinates
o ^A/ ^at vu=x':+y-:*t-- ^at
aca)a
i.2=+.+*+ &&a
v * t - or# -!,. r(+ - *,. u(+ -!t
dr= &dydz da*: Mydz da,
=tdxdz dar: tdxdy Cvlindrical Coordinates
ir-. vu= p--+e-=;*2-= ^At . r1fu ^At op paQ
az1A , lAA6
dA"Y.A=- pop ')-;ad* ^ (pA^ a
v, A
=be+ -%,. "pd0 A"'A or% - %t * z1!!6t^> - !1"t
dp pap pd6t
dr= NNMz dor: lpd@z day: tdpdz
da,: INNO h=cos@+sinfr 6 =-sn7;-+cos@
Snherical Coordinates
; vu=rA*o; ^a/ .ldt o 1 A) do*a rri"e
aoi
- A =i * u' *, - ## @rnoA,,.##
i,
A =#r# ginzA,, - #t.ir# # -* uu,,. 9r* eA,) - #j
dr: r2sin*drdMQ da, : tr2sinM*dQ dae:
+rsinffitd| doo: *drdg f =sind cos@+sind sinfi+cosfi 6 =coslcosfi+cosd sinfr-sine
6 =-sinfr+cosfi
...9/-
96
[zcr
304E]LAMPIRAN
-9-
Important Eguations
Maxwell's Equations:
=;. v.D=pr V.E=o V*E =1- dt'dt vrfr=Jr*4
Lorentz
Force:F=q(E+ilxB)
Equation
ofContinuity: i.i, *o4"1 =0
dt
Coulomb's Law: F" =2 ,nn'R^ (for
a collection of point charges)' 7 4rcoRi
F" =:L S7(7')!'ds' (for
a line chargedistribution)
" 4neol, R'
Fo
= ;4 yT)\da' (for
a surface chargedistribution)
' 4ne, !,
.R'F"
==L yT2\dt' (for
a volume chargedistribution)
, 4reo N, R,
ElectricField: E-Fn
q
Electric Flux: q" = lE .aa
Gauss'Law: {E.aa ={
(integralform)
v .E = A')
(difterentialform) to
g'7
...10/-
LAMPIRAN -
IO- IZCT
3O4E]scalar Potential: dV) =Z,r+
" (for
a collection of point charges)|
4neoR,r,-\ | 1)"(f')ds' ,i
Q\r ) --
4"rr lr,-= (for
a line chargedistribution)
1 " o(F')da' ,.
Q(F)
=
^r%l =\f (for
a surface chargedistribution)
!/-\ I 1p(V')dr',r
Q\r )
=
^"r, ',-=-
(tbr
a volume chargedistribution)
Potential Enerry: tl
"(F)
=qoe) (for
an isolated point charge)rr 1s.
u
, =; Lq,Q,(V,) (for
a collectionof
point charges) U1.
"
=; Jr),(F)Q(V)ds (for
a line chargedistribution)
:
U
"
=i lo(r)Sf)do (for
a surface chargedistribution) l.
U
"
=, lO(D6(4dr (for
a volume chargedistribution) u"
=a€oEt
I (energy densityin
an electricfield)
U"
= [u"dr
(total energy)MultipoleMoments: e=1u,or e= tsv [ut o, g= foda or e= [odr
(monopole)F
=\,q,1 or
P- [.trat or p = [oraa or F - lOr-dr
(dipole)'Lsv
Boundary Conditions: E,, -
Eu =0 and E,z-
Ent =9 lelectric field)
€o
0, =
A
(scalar potential)B,z- Bnt=0 and E,r-E,r= poRxfi
(magnetic induction)...ru-
9li
lzcT
304EJLAMPIRAN - 1I.
Electricity in Matter: p
=py
+pu
(free charge and bound charge)h
=-i -F
andot = F.fi
@ound charge densities)D
= eoE +F lOen*don
ofelecric
displacement)D
= rc"eoE =
eE
(for anl.i.h.
dielectric) u, =1P l-
'g
(energy density in matler)-
fiD
aa=Qr.,
and V.D
=pr
(Gauss' Lawsfor D) Erecrriccurrent: I=+= lj.aa= IR.a
dtJ
i=fr k=oi
(currentdensrty)IB =
Rda= idt
(current elements)j, = oE (ohm's Law)
MagnetostaticForce: Fr,-, =#{:*#A
Magnetic Induction:
U =#!!g;! (for
a filamentary current)B =
+ 4r I' S.R' *aa' R' (for
a surface cunent)E =
+ Si' ^-4at' (for
a volume current)4tr,), R.
Ampere's Law: {8.* = FoI,
(integralform)
c
i"F
=Hoi (differentialform)
...rzt-
99
lzcT
304EILAMPIRAN
Vector Potential: E =i * tr
- lJn
rI'dS'
l=!-:-d - (forafilamentarycurent)
4nl,
t_ft
2
=+ 4na'
Lry
R(for
a surface current)A
=+ 4rv'
t,+
R(for
a volume current)Magnetic Flux: Au = IE.aa
Faraday's Law:
", = {E, .fi
=+
(integral form)VrE =4 (differentialform) dt
Magnetism in Matter: i = J,
+J^
(free current plus magnetisation current)i^ = i * frI
(magnetisation volume current density)R,
=M *i,
(magnetisation surfacet density)fi =
1t01fr+ fu) (definition
of magneticfield)
$
=po(E
+M)
=lto(t+ Z)E
=pFI (for l.i.h.
material)-12-
-ooooooo-